Strategies for Number Puzzles of all kinds
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Sunday 1-May-2016

... by: JC Van Hay

0. G3=9; Pointing{9AC7} -> -9DEF7
1a. G8≠3 otherwise the Double Exocet (4578){G45,H13,Columns269} -> G2={}
1b. Pointing{3G45} -> -3H46; HP(23-45678)H78
2a. G45=34 -> 1 solution via Skyscraper{4CJ2,4CH9} -> H9=4; HP(18-26)E19; Skyscraper{2AD1,2CD4} -> C4=2
2b. G45=37 -> 0 solution via Skyscraper{7DJ2,7DH9} -> H9=7; Swordfish{8B13,8F134,H36} -> H6=8
2c. G45=53 -> 0 solution via Swordfish{5ACJ2,5AC6,5ACH9} -> H9=5
2d. G45=83 -> 0 solution via Swordfish{8DEJ2,8DE6,8DEH9} -> H9=8; G2=7/G2=5/G2=4,HP(57-89)F78

Saturday 30-Apr-2016

... by: ray

Mistake! The following 3-element non bi-location cell set solutions were found: BDF4 = (5,8,8), DEJ6 = (3,4,5) using basic strategies.

Saturday 30-Apr-2016

... by: ray

1. Use only basic strategies and the forcing bi-location cell set method.Start
with D4{12389} - bi-location cell for 2,tri-location cell for 1,2,3 and 9.Form,
progressively, the 3-element bi-location cell set D4F8H8(only force the run out values) until D4F8H8 = (9,7,3) which gives the solution. Other bi-location cell solutions found were : A3C7J5 = (6,4,7), A3H8J5 = (6,3,7),
B1D4F8 = (4,9,7) ,B1D4J5 = (4,9,7).
2. Using this solution and basic to extreme strategies,the 1-cell solutions:
G9 = 7, J7 = 8(Exocet values) were found.

Saturday 30-Apr-2016

... by: anybody1

1F5

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