Strategies for Number Puzzles of all kinds
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Monday 15-Sep-2014

... by: newby

9D6, 7D2, 7J1, 9E1, 2B1, 7H9, 7G6
4D7, 6(C8, A8, A9)>contradiction therefore 2D7
2E3, 1(E4, F5)>contradiction therefore 2f2 solves

Saturday 13-Sep-2014

... by: JC Van Hay

7 Singles

J2=1 -> J8=5=E7, J9=8=B7, C7=1; B8=7=C4, C8=9; A1289=468 !
:=> HP(14)J46; 5 Singles; NP(14)A6C5; 3 Singles

[3D8=3D9 - (3=8)J9 - (8==2)BCDH7]-2D8
6 Singles; HP(36)C23; 6 Singles; NP(14)BC7

UR(68)AE89=(15)E8; Singles to the end.

Saturday 13-Sep-2014

... by: JPF NAPERVILLE

#150 (a milestone) was readily solved by:
1. using steps 1-6 to add in 7fill-ins
2.focusing on the quint in row J and solving it via a 8 in J8 which
yielded 3fill-ins and a pair
3. using steps 1-6 ONLY then solved the puzzle.
Thus, once again the use of just basic 1-6 step logic plus solving a
combination allowed basic steps 1-6 to solve the puzzle. No need to
even try steps 7-35!!

Saturday 13-Sep-2014

... by: ray

#1. Use basic strategies and bi-location/value tool to get working board.
#2. Select cell H3{1569}- bi-location for 9, tri-location for 1. Forcing
H3 = 1 gives the solution.
#3. Using this solution,with basic strategies,forcing the following bi-
location with the indicated values: A2 = 1, J2 = 5, J8 = 8 gives 1-cell
solutions; other 1-cell solutions found are: A6 = 4,C7 = 4, E3 = 5,
F8 = 5, G7 = 5. Some 2-cell solutions found are: BC3 =(4,6),
BC5 = (8,1), GH7 = (5,9), G5J4 = (5,4).



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