Strategies for Number Puzzles of all kinds
Print Version
Latest Apps

Valid XHTML 4.01 Transitional


Post an idea here...
Your Name or Handle

Your comment, idea or question

Please enter the
letters you see:
Enter these letters
Remember me

Please keep your comments relevant to this puzzle.
Email addresses are never displayed, but they are required to confirm your comments. To state your solve time use the smaller form at the top right of this page." & vbNewLine & _ Line breaks and paragraphs are automatically converted ? no need to use <p> or <br> tags.

Saturday 25-Jun-2016

... by: ray

Also C7 = 2.

Saturday 25-Jun-2016

... by: JC Van Hay

0. Pointing{9B1} -> -{9r1c45}; HP(89-2347)r78c9
1. Double Exocet (4567){r3c23, r2c89, C167}

r3c2|3=a -> Swordfish{aC167} -> [ar1c7==ar2c6] -> -{ar1c45, ar2c89}
r2c8|9=a -> Swordfish{aC167} -> [ar1c1==ar3c6] -> -{ar1c45, ar3c23}
{a,b,c,d}={3,6,7,9} :
r3c23=ab -> r1c7.r2c6=ab -> -{(ab)r1c45,(ab)r2c89}
implies or is implied by
r2c89=cd -> r1c1.r3c6=cd -> -{(cd)r1c45,(cd)r3c23}
-(abcd)r2c1 or r2c1=1; -(abcd)r3c7 or r3c7=2; -(abcd)r1c45 or r1c45=12

1b. Multifish/Rank 0 Logic : the 12 constraints {(4567)C167} are covered by the 12 constraints {r1c17, r23c6, 4R47, 5R45, 6R58, 7R78}
-{4r4c28.r7c5, 5r4c234.r5c39, 6r5c35.r8c28, 7r7c3.r8c48}

1c. The solutions of the multifish also exclude {5r4c6, 8r45c1, (12)r5c6}
Proof :

2. Updating :
Pointing{8B4} -> NP(13)r7c3.r8c2 -> -{3r9c23}
HT(467-123)r269c8 -> HP(23-47)r8c8.r9c9 -> NP(23)r59c9 -> -{3r6c9}
Swordfish{6R58C8} -> -6r2c6

3. [9r2c5=9r7c5-(9=8)r7c9-8r7c1=(8-6)r8c1=6r8c7-6r9c8=6r2c8]-6r2c5; 2 singles
4. [8r7c1=(8-9)r7c9=9r7c5-(9=4)r2c5-4r9c5=(4-7)r9c8=7r7c7]-7r7c1; 6 singles
5. [4r2c9=4r2c6-4r7c6=(4-7)r7c7=7r1c7]-7r2c9=7r1c79-7r1c3=7r3c3
6. [1r5c8=1r4c8-(1=2)r4c6-2r8c6=2r8c8]-2r5c8=XWing(2C68)-2r4c4
7. [(2=1)r1c5-1r1c4=1r46c4-(1=2)r4c6]-2r5c5; 8 singles
8. [8r4c4=8r4c3-(8=3)r5c3-3r5c8=3r4c8]-3r4c4
stte of a unique solution

Saturday 25-Jun-2016

... by: ray

1. Use only basic strategies and the forcing bi-location cell method.Start with G7 - bi-value and tri-location cell for 4.Progressively form the 3-element
bi-location cell set G7E5B4 by forcing the 1-cel to 3-cell values,only force the run out values,until G7E5B4 = (4,1,7) which gives the solution.Other bi-location cell set solutions found were : B4E5H1 = (7,1,7),E5G37 =(1,1,4), A2G37 = (6,1,4). N.B: using basic to extreme strategies,A2 = 6, B4 = 7 gave1-cell solutions.
2. Using this solution,with basic strategies,the following non bi-location cell set solutions were found: BDF4 = (7,8,3),A5B4C6 = 2,7,6) E5F4J5 =(1,3,4),BEH6 = (4,5,1), BEJ5 = (9,1,4). N.B: using basic to extreme strategies,the following 1-cell solutions were found:B6 = 4,A5 = 2,B1 = 2 .

Saturday 25-Jun-2016

... by: anybody1

1A4 2A5 4G7...


Each week a new 'unsolvable' will be published and the previous will be accessible here from this archive section. If you like very tough puzzles, these are for you.
Share and Enjoy

Post a Comment using Facebook...

Page created on 03-May-2011, last modified on 03-May-2011.
All puzzles on this site are trademarked and copyright
and cannot be reproduced without permission.
Copyright Syndicated Puzzles Inc, 2011-2015