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Saturday 14-Jan-2017

... by: ray

1. Use only basic strategies and the forcing bi-location cell set method.Start
with H1{4569} - bi-location cell for 4,tri-location cell for 5,6 and 9.Progress-
ively form the 3-element bi-location cell set H1G7A1,forcing only the run out
values for the 1-cell to 3-cells until H1G7 A1 = (6,9,1) which gives the solution.Other bi-location cell set solutions found were: C9D4G7 = (6,3,9), D4G7H1 = (3,9,6). N.B.: Using basic to extreme strategies,H1 = 6, C9 = 6, D4 = 3, F8 = 6 gave 1-cell solutions.
2. Using this solution,with basic strategies,the following non bi-location cell
set solution was found: C8G7H9 = (4,9,5). N.B. : Using basic to extreme strategies,B9 = 3, C2 = 8 gave 1-cell solutions.

Saturday 14-Jan-2017

... by: JC Van Hay

0. B6=9
1. Exocet (3468){A46, Col358} :
1a. aA4|aA6 -> Swordfish{aCol358} -> aB3==aC8 -> -{aB79, aC12}
1b. Structure of the 1st band :

| 127cd 127cd 7cd | ab 5 ab | 17cd 1cd 9 |
| 1(46) 5 a|b | 7 cd 9 | 1cd 2 1cd |
| 7cd 7cd 9 | 1 cd 2 | 57(48) b|a 57(36) |

where{abcd}={3468}

1c. Inferences :
No exclusion in the target cells B3.C8
NT(1cd)B579 -> -{1A78, 1B1}
NT(7cd)C125 & NT(7cd)C12.A3 -> A7=7, A12=12
B1=4|6(=b|a) -> C79=5(a|b), C8=4|6 or -{(36)C8}

Analysis of the puzzle from the base cells of the Exocet :
2a. 3A4 -> 0 solution via B1.H12=46 -> CD1=72
2b. 3A6 + 6B5 -> 0 solution
2c. 3A6 + 6C5 -> 0 solution via XWing{8Row28} -> -{8GJ5}
2d. 8A4|8A6 -> 0 solution via Pointing{8Box3} -> H2=8
Conclusion : A46=46; G5=6; B1.H12=46 -> CD1=72; 16 Singles; XWing{2Row57} -> -{2F4, 2J5}; F4=5

Structure of Row 1 : 123456789 ?
3. A3=8 -> 0 solution; A3=3 and stte of a unique solution.

Saturday 14-Jan-2017

... by: rikroeger

I was wrong ...
4<>r1c1 because 4=r1c1-->6=r1c3-->8=r1c4-->=r2c3
3<>r1c2 because 3=r1c2-->4=r1c4-->4=r2c3-->3=r2c5-->7=r3c1-->8=r3c2-->=r1c3
6<>r1c2 because 6=r1c2-->1=r1c8-->9=r2c6-->8=r3c2-->6=r3c5-->=r1c3
4<>r1c3 because 4=r1c3-->9=r2c6-->1=r2c9-->8=r3c2-->6=r3c5-->5=r3c7-->=r4c4
8<>r1c3 because 8=r1c3-->9=r2c6-->1=r2c9-->7=r3c1-->3=r3c2-->5=r3c7-->=r3c7
3<>r1c4 because 3=r1c4-->3=r2c3-->4=r2c5-->9=r2c6-->6=r2c9-->4=r3c1-->8=r3c2-->=r1c6
8<>r1c4 because 8=r1c4-->8=r2c3-->4=r2c5-->7=r3c1-->=r1c3
3<>r1c6 because 3=r1c6-->1=r2c1-->8=r2c3-->=r1c3
8<>r1c6 because 8=r1c6-->8=r2c3-->9=r2c6-->4=r2c7-->7=r3c1-->=r1c2
1<>r1c7 because 1=r1c7-->3=r1c3-->8=r2c3-->=r4c1
8<>r1c7 because 8=r1c7-->1=r2c1-->8=r2c3-->=r4c1
1<>r1c8 because 1=r1c8-->6=r2c3-->=r2c7
1<>r2c1 because 1=r2c1-->=r1c2
6<>r2c1 because 6=r2c1-->=r2c7
3=r4c4 because 3<>r4c4-->=r4c4
4<>r5c3 because 4=r5c3-->7=r5c5-->=r5c7

Saturday 14-Jan-2017

... by: rikroeger

hallo
I only use nishio and singles
3 = r1c1 because 3<>r1c1-->8=r1c1-->9=r1c3-->=r2c6
5<>r1c3 because 5=r1c3-->=r1c4
9<>r1c3 because 9=r1c3-->=r1c6

Saturday 14-Jan-2017

... by: anybody1

1 cell stte: 2A2 3A3 7A7 8A8 6D2 7G2 8J4 7J5...

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