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Post an idea here... Discussion... Saturday 18-May-2013... by: JC Van Hay... UR(35)BH56=8B5 ...Saturday 18-May-2013... by: JC Van HayFWIW, instead of using the straightforward UR(35)BH56=8A5 in #4 :#4. J5=7->UP57; Broken Wing 3AE1+3F24+3A4 :=> J6=7; UP36; NP(89)D46; UP81 Saturday 18-May-2013... by: rayGet working board using basic strategies.Choose cellG4{178} - bi-location cell for for value 1. Forcing G4 = 1 or 7 gives an inconclusive result, G4 = 8 gives a solution. Using this solutuon(with basic strategies), other 1-cell solutions are: J3 = 8 ,J6 = 7 , J8 = 3, J9 = 2, E5 = 7, A7 = 9, A8 = 2, A4 = 7; somme 2-cell solutions are: F12 = (5,8), C23 = (6,4),DE9 = (5,8).Saturday 18-May-2013... by: JC Van Hay#1. B4=4; UP24; HP(45)FJ7; NT(359)H456; LC(456)#2. Kite(7C67.AF8) :=> -7F6 #3. J2=7->UP40; Chain[5] : 9A7=9E7-9E3=HP(59-6)AD3=6C3-6B2=6B9 :=> A7=9;->Contradiction(Singles); G1=7 #4. J5=7->UP57; B5=3or5or8->Contradiction(Singles) :=> J6=7; UP36; NP(89)D46; UP81 |
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