Strategies for Number Puzzles of all kinds
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Saturday 22-Oct-2016

... by: ghfick

(using David P. Bird's JE Compendium)
(after one basic move)
(2679) JE4 : r79c8, r1c7 r4c9; r23c9, r4c8, r8c7
cross lines: r148
cover houses: (2) c45, (6) c13, (7) c34, (9) c15
r1c7<>8 r4c9<>1 r4c8<>8 r8c7<>1 (non-base digits in target cells)
r1c8, r8c9, r56c7 <>2679 (known base digits that see all base cells or all target cells)
r3c1<>6, r5c1<>9, r7c1<>6, r7c1<>9, r6c3<>6, r7c3<>6, r9c3<>7, r3c4<>2, r3c4<>7, r5c4<>7, r7c4<>2, r3c5<>2, r6c5<>2, r9c5<>9
(known base digits in non-'S' cells in their cover houses)
r4c9<>9 (target node digit missing in mirror cells)
(basic moves)
(4=8)r2c5 - (8=4)r3c2679 => r3c45<>4
(1=4)r9c5 - r7c4 = (4-5)r5c4 = r6c5 => r6c5<>1
(5=3)r3c4 - r3c5 = (3-9)r8c5 = r1c5 => r1c5<>5
(9)r1c7 = r1c5 - r2c6 = r7c6 => r7c7<>9
(9)r2c9 = r1c7 - r1c5 = r8c5 - r8c1 = r4c1 => r4c9<>9
(9)r1c5 = (9-3)r8c5 = r3c5 - (3=5)r3c4 - r5c4 = (5-9)r5c9 = r2c9 => r1c7,r2c6<>9
(basic moves)
(5=6)r1c1 - (6=9)r8c1 - r8c7 = (9-5)r9c7 = r7c7 => r7c1<>5
(basic moves)
(2=7)r2c6 - r5c6 = (7-5)r5c9 = r5c4 - (5=3)r3c4 - (3=2)r8c4 => -2 r1c4<>2
(1=4)r5c4 - (4=8)r6c6 - (8=1)r6c7 => -1 r5c7<>1
(basic moves)
(1=4)r2c3 - (4=8)r2c5 - (8=1)r4c5 => -1 r4c3<>1
(1=4)r2c3 - (4=3)r6c3 - (3=1)r5c1 => -1 r2c1<>1

Saturday 22-Oct-2016

... by: ray

B9 =9.

Saturday 22-Oct-2016

... by: ray

1. Use only basic strategies and the forcing bi-location cell set method. Start with B6 - bi-location cell for 9, tri-location cell for 7 and 9.Progressively
form the 3-element bi-location cell set B6E1J7,forcing only the 1-cell to 3-cells run out values(no contradiction values) until B6E1J7 = (2,1,9) which
gives the solution.Other bi-location -cell solutions found were: E1F9J7 = (1,2,9), E4F9J7 = (4,2,9), B6E1H5 = (2,1,2). N.B: using basic to extreme
strategies,B6 = 2, J7 = 9 gave 1-cell solutions.
2. Using this solution,with basic strategies,the following non bi-location set
solutions were found: CFJ7 = (7,1,9), B2CD1 = (7,8,6). N.B: using basic to extreme strategies,C7 = 7,B9 = (Double Exocet value) gave 1-cell solutions.


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