SudokuWiki.org
Strategies for Popular Number Puzzles

#717, September 26 - October 2, 2026:
The Weekly 'Unsolvable' Sudoku Puzzle

by Richard Kröger, guest compiler

WARNING: This is the Weekly 'Unsolvable' Sudoku, rated above 'Extreme'.
This is currently unsolvable by my solver, except perhaps with trial and error strategies.
Using the solver will not help you. (much).

Changes March 2026

Due to the introduction of Forcing Nets many Weekly Unsolvable puzzles can now be solved. I have flagged all the Sudoku ones which are solvable. I am struggling to make any new ones so we'll have to see if the Weekly can continue. The point of the Weekly was to provoke discussion and new ideas, so that is progress. But my solution is unlikely to be optimal so alternatives are welcome.

Archive

Each week a new 'unsolvable' will be published and the previous will be accessible here from this archive section. If you like very tough puzzles, these are for you.
Share and Enjoy
Supporter Members have access to all these puzzles going back to number 1.

Discussion...

Post an idea here...
Your Name or Handle

Your suggestion, idea or question

Please enter the
letters you see:
arrow
Enter these letters



Please keep your comments relevant to this puzzle.
Email addresses are never displayed, but they are required to confirm your comments. To state your solve time use the smaller form at the top right of this page. Line breaks and paragraphs are automatically converted ? no need to use <p> or <br> tags.

Saturday 26-Sep-2026

... by: Norman Powell

AS's Solver only finds Hidden Singles 8H1 & 4H7.
My Solver:
Confined to Box: Value 3 confined to Column 5 and Box 2, eliminate 3G5 & 3J5.
[AS's Solver should have picked this up as a Pointing Pair?]
Alternative Inference Chain [Placed before Forcing Networks in my method order]:
3J1 has weak links to both ends of chain, which would cause a contradiction so eliminate.
Chain: -1H3+1H4-2H4+2J4-7J4+7J5-5J5+5J1-
Grouped X-Cycles [Placed after AIC in my methods order]:
1A3 & 1B3 has weak links to both ends of the following chain: which would cause a contradiction so eliminate:
-1H3+1H4-1E4+1[E2 E3]-1D1+1[A1 B1]-
Forcing Network Pass 1: Finds nothing until testing 9C3 for being ON, when it finds the solution:
547932168186574293329681547718346952693125784452897316265413879871269435934758621
[This is equivalent to AS's Bowman's Bingo]
I am not sure why AS's Solver did not proceed further?
Page created on 03-May-2011, last modified on 30-May-2024.
All puzzles on this site are trademarked and copyright
and cannot be reproduced without permission.
Copyright Andrew Stuart @ Syndicated Puzzles, Privacy, 2007-2026