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Sunday 28-Aug-2016

... by: cenoman

Using David's JE Compendium:
Double Exocet (3457)JE4: D23, E6, F7 & F45, E1, D7
D6=9, F1=1, E89=19 (cells in sight of all 4 base cells or all 4 target cells) UP 59 solved cells with basic techniques (locked candidates, locked sets)
End with SC (5)A3=A5-F5=E4 =>-5E3 stte

Sunday 28-Aug-2016

... by: johnny

Ray, c6 cannot be 7 because c2 = 7

Saturday 27-Aug-2016

... by: ray

D6 =9 gives a 1-cell solution with basic to extreme strategies.

Saturday 27-Aug-2016

... by: ray

1. Use only basic strategies and the forcing bi-location cell set method.Start
with F8{1567} - bi-location cell for 6,tri-location cell for 1.Progressively form
the 2-element bi-location cell set F8C6,only force the 1-cell to 2-cell run out
values (no contradiction values ) until F8C6 = (5,7) which gives the solution.
Other bi-location cell set solutions found were: CE3F8 = (1,3,7), C3E4F8 = (
1,5,7), E4F8H9 = (5,7,8), C6F8H9 = (5,7,8) N.B: using basic to extreme strategies,F8 = 7 gave a 1-cel solution.
2. Using this solution,with basic strategies, the following non bi-location cell set solutions were found: A9BF8 = (3,5,7), H9J59 = (8,5,9).

Saturday 27-Aug-2016

... by: JC Van Hay

Optimized solution :
1. The solutions of the Double Exocet (3457){D23, F45, Columns167} imply D6=9, F1=1

2a. 5 singles
2b. NP(35)C16; C7=8
2c. HP(18)G8.H9; 28 singles
2d. XWing{5RowsAE} -> -{5F5}; F5=3; stte of a unique solution

Saturday 27-Aug-2016

... by: JV Van Hay

1. The solutions of the Double Exocet (3457){D23, F45, Columns167} imply
1a. D6=9, F1=1; E89=19
1b. NP(35)C16; C7=8
1c. NP(47)GH7; NP(35)DF7
1d. NT(347)G167, NT(457)H167
1e. Swordfishes{(47)Columns167} -> HP(47)E16
1f. 34 singles

2. XWing{5RowsAE} -> -{5F5}; F5=3; stte of a unique solution

Saturday 27-Aug-2016

... by: anybody1

5B8 3C1 5C6 8C7 9D6 1F1 4G7 7H7

Saturday 27-Aug-2016

... by: anybody1

hard! 1 cell + stte: 3D7 9E8 1E9 7F8

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