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Saturday 23-Jul-2016

... by: JC Van Hay

0a. Pointings{3Box5, 3Box9} -> -{3D13, 3G5}
0b. Swordfish{8RowsAEH} -> -{8DF1}

1. The solutions of the Double Exocet (4589){E56, F79, Columns248} imply
1a. E8=2, F4=6, D13=26
1b. E6=5 or F79=B8=E2=5 -> -{5E3} or
Swordfish(5)[E6=D46-D8=B8-B2=EF2]-5E3
1c. -{4B59.C179, 5B39, 8G5, 9C67.G35}
1d. HP(89-126)G24; HT(459-3)BCD8
1e. 5D8=5B8-5B2=HT(589-4)EFG2=*[4D4=*XWing(4BC24)-4BC8=(4-9)D8=9C8-9C4=HP(89)DG4] -> -{5D4}; J4=5

The puzzle is now "solvable". Or, for example :

2. Updating :
G8=3
Claiming{1BC4} -> -{1B5}
HT(13-27)BC9; HP(45-67)H79; HP(27-45)AG9
NP(27)A9.C7 -> -{(27)A7}; NP(67)B5.C6 -> -{7A56}
Swordfish(9)[G2=G4-C4=C8-A7=F7]-9F2

3. AIC[5A3=(5-3)F3=3B3-3B9==5B8]-5A7.B2; 2 singles
4. AIC[9F6=(9-3)F3=3B3-(3=1)B9-1B4=(1-9)C4=9C8]-9A7.D8; 15 Singles
5. XYWing(267)AD1.B3-(6=2)D3-2G3=2J12-2J7; D1=6
6. XYWing(267)J27.C7-(2=6)B3; 8 singles
7. XYWing(167)J17.G3-(6=7)G7; stte of a unique solution

Saturday 23-Jul-2016

... by: ray

1. Use basic strategies and the forcing bi-location cell set method.Start with
H1{678} - bi-location cell for 8,tri-location cell for8.Progressively form the
3-element bi-location cell set H1D9A5,only force the 1-cell to 3-cell run out values(no contradiction values) until H1D9A5 = (7,5,9) which gives the solution. Other bi-location cell solutions found were: B3D69 = (7,9,5), D9H17 = (5,7,5), C4H17 = (4, 7,5). N.B: using basic to extreme strategies,
the following 1-cell solutions were found: B3 = 7, C4 = 4, D6 = 9, D9 = 5,
H1 = 7, E1 = 8, F1 = 4.
2. Using this solution,with basic strategies,the following non bi-location cell set
solutions were found: D136 = (6,2,9), D3EF1 = (2,8,4), D89G7 = (4,5,7), G49H7 = (9,2,5). N.b: using basic to extreme stategies,the following 1-cell
solutions were found: D1 = 6, D3 = 2, E1 = 8, F1 = 4, D8 = 4, E8 = 2, F4 = 6,
F7 = 9(Double Exocet value).

Saturday 23-Jul-2016

... by: kozo kataya

This is a HARD puzzle not like previous week's.
Can't solve without a brute-force like technique,
Anyway find the solution out of 1/87 possibilities.
[4F1] is the answer, and for stte [2D3+9E2+4F1].
However i ashame not find any logical procedures.
Is this puzzle so called EXOCEC ?

Saturday 23-Jul-2016

... by: anybody1

6D1 2D3 ...

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