... by: neo

My sudoku solver didn't have any problems with this one. A different program also tells me there is only one solution.

... by: Mark7

1A1, 2E5, 3G5 leads to logical solution

... by: newby

using 2 (E4, E5) and 9 on row E;
6 (B4, C5) and 6 (D9, E9) against (1,3,4)F1 yields:
2E5, 9E4, 6E9, 6B4, 4F1 solves

... by: ray

Billy Mac, please send me your system to: craynyl@gmail.com.

Thanks

... by: jethro

Billy Mac, please send me your system jethro_bodine@juno.com

... by: Billy Mac

How do I give you my email address without everyone knowing it?

... by: Billy Mac

I solved this puzzle, because I have been doing puzzles for about 10 years and I have diligently observed that there are 2-3 patterns that can be relied on to cancel numbers without seeing ahead of time the logical deduction. If you give me an email address I will send you the sequence of my entries, but I will not at this time reveal my patterns for elimination,
Sincerely, Billy Mac

... by: JC Van Hay

Re-Typo : read F1=4; UP30 :(

... by: JC Van Hay

Typo : read F1=1; UP30

... by: JC Van Hay

#1. All Cells Rank 0 Logic : the 15 cells ADFH1457-D1 are covered by the 15 sets 27RowA, 37RowD, 3RowF, 69RowH and 14Column1, 45Column4, 18Column5, 58Column7 :=> 24 eliminations : -27A29, -37D169, -3F8, -6H2 and -14DGJ1, -45BEG4, -18CEG5, -58CG7
:::. D1=6=F9, D7=7; UP24
:::. LC(3D45,3J89,6H45)-3EF45,3G789,6G45; Skyscraper(3BF1,3CF7)-3B89C2
:::. NT(135)E238-15E6; HT(568-1247)G23H2; NQ(2379)G1457-279G689; HT(237-1458)BCJ9
#2. F1=1or3->Contradiction(Singles) :=> F6=4; UP30

F1=1->A2=1,F4=4,F5=8,F7=3,F8=5=B6,C6=8,D6=1=H5,C5=6,B4=9,B8=8; Row A is devoid of 8 !
F1=3->F4=4,B2=3=E8=J9=C7,G7=2,H7=9,H4=6=B3,H5=1=D6,B6=5,F5=8=A7; Row B is devoid of 8 !

:::. ER(8F5=8F8-8BCB=8A79)-8A5; C6=8; UP31
:::. NP(27)A45-27A17B4C5; UP35
:::. UR(27)AE45=9E45-(9=7)E6; UP81

... by: ray

#1. Apply basic strategies and bi-location tool.
#2. Need to form, progressively, a 4-bi-location cell set E59G5J8. Forcing the various 4-cell values
gives inconclusions or contradictions untill E59G5J8 = (2,6,3,3) which gives the solution.
#3. Using this solution,with basic strategies, the following 2-cell solutions are found: GH4 = (7,4),
GH1 = (2,9), GJ1 = (2,7), D46 = 3,4), GJ6 = (1,9).

... by: newby

4H4, 3G4>contradiction
4H4, 3G5, 4D6, 4F1
6D9 inconclusive
6E9 solves