... by: ray

1. Use only basic strategies and the forcing bi-location cell set method. Start
with E8{2389} - bi-location cell for 8,tri-location cell for 3 and 8.Progressively
form the 3-element bi-location cell set E8A9B2,forcing only the 1-cell to 3-cell
run out values(no contradiction values) until E8A9B2 = (3,5,8) which gives the solution.Other bi-location cell solutions found were: A9B2E3 = (5,8,9).
2. Using this solution,with basic strategies, the following non bi-location cell
set solutions were found: D56J5 = (2,9,7), G5J26 = (5,5,8), A9EF8 = (5,3,9).
N.B: using basic to extreme strategies,J5 = 7 gave a 1-cell solution.

... by: JC Van Hay

Only using the exclusions by the solutions of a digit or of a unit :

1. Solving row D :
1D5 + 8D69 -> 0 solution; D7=1

8E8 + 5H7 -> 0 solution
8E8 + 2H7 + (17)H8 -> 0 solution; D9=8

2D1 -> 0 solution
9D1 + 2H7 -> 0 solution
9D1 + 5H7 + (36)B7 -> 0 solution; D1=6
5 singles

2. Solving Column 7 :
6B7 + 5H7 -> 0 solution
6B7 + 2H7 + (17)H8 -> 0 solution
6J7 -> 1 unique solution

... by: anybody1

1 cell solution: 5A9 5B4 5C3 5J2