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A super new pattern discovered by **shye** over at the New Sudoku Players Forum and posted in November 2021. The full write up is on this thread.

To quote

Take row A and column 1 and consider candidate 9. Clearly the cell marked with

The conclusion is that 9 must appear at least once in the three cells X, Y or Z.

Knowing one candidate fits in X, Y and Z at least once doesn't get us very far since "there is no common seen cell to eliminate a candidate" but the pattern - a 'firework' - can explode outwards from the intersection if multiple candidates share the intersection. In the diagram above candidate 8 also works on the same logic as 9.

That gives us an interesting weak link between 8 and 9 in**X** that obliges at least one of **Y** and **Z** to be 8 or 9. We could include this link in AICs and other chaining strategies.

That gives us an interesting weak link between 8 and 9 in

The magic starts when there are three candidates exhibiting the same firework pattern. Following **Shye**'s thread I'll reproduce "Triple Laser", the puzzle formulated by forum contributor **Qinlux** and then one of my own next.

A1, A9 and J9 exhibit the firework pattern with candidates 1, 2 and 3. We know that each candidate must appear at least once in these three cells and we have three firework candidates so that makes a classic**Locked Set**. We can't be certain which cells will ultimately be 1, 2 or 3 (except 3 is already excluded from J9) but a locked set excludes other candidates, so we can remove them. This greatly simplifies the rest of the puzzle which would otherwise require laborious chains.

Note that 1, 2 and 3 are absent from the blue shaded cells. This is how to spot the pattern. Also note that like triples in other strategies, it is not required that {1,2,3} be present in both wing cells, merely that they are present*across* the three cells. The pattern does require {1,2,3} in the intersection cell.

A1, A9 and J9 exhibit the firework pattern with candidates 1, 2 and 3. We know that each candidate must appear at least once in these three cells and we have three firework candidates so that makes a classic

Note that 1, 2 and 3 are absent from the blue shaded cells. This is how to spot the pattern. Also note that like triples in other strategies, it is not required that {1,2,3} be present in both wing cells, merely that they are present

This Triple runs off {3,7,8} from the intersection cell F4. I've marked the cells which lack these candidates in light blue to highlight how outside box 5 there is only one cell in each of row F and column 4 where {3,7,8} can fit. The eliminations are in yellow.

Triple Fireworks: The three cells [F1|F4|C4] are a locked set that must contain {3/7/8} therefore

4/5/6 removed from C4

Out of some 45,000 hard puzzles in one test set I found just over 300 examples, comparable to Naked Quads.

Taking the idea to the next level - a quadruple firework display. Now, I've searched through thousands of difficult puzzles and not found another example beyond the demonstration puzzle *"Cobra Roll"* created by **jovi_al**, so I am using that puzzle to illustrate.

Actually, this is two double fireworks that happen to align on four cells. Down in the bottom left corner on J1 we have two fireworks on candidates {1,2}. I've drawn the cells that don't contain 1 or 2 in light brown. The second double firework hangs on D6 and the candidates {3,4}. The wings of both these patterns are the same two cells: D1 and J6.

While we have exactly four numbers in four cells the eliminations are a little bit more complicated than the triple. The intersection cells eliminate everything that is not a firework candidate, so J1 will keep only {1,2} and D6 will keep only {3,4}. While D1 and J6 will keep all four candidates {1,2,3,4}, if not already removed.

This pattern is rare because it not only requires four fireworks, they must be aligned just so, too many coincidences. But the logic is enjoyable.

There are a good many novel uses of this pattern in more advanced ways that I don't need to duplicate here, the thread is clear. For this release of the solver I've included the two types above and will further document when or if I can code up more variants.

Actually, this is two double fireworks that happen to align on four cells. Down in the bottom left corner on J1 we have two fireworks on candidates {1,2}. I've drawn the cells that don't contain 1 or 2 in light brown. The second double firework hangs on D6 and the candidates {3,4}. The wings of both these patterns are the same two cells: D1 and J6.

While we have exactly four numbers in four cells the eliminations are a little bit more complicated than the triple. The intersection cells eliminate everything that is not a firework candidate, so J1 will keep only {1,2} and D6 will keep only {3,4}. While D1 and J6 will keep all four candidates {1,2,3,4}, if not already removed.

This pattern is rare because it not only requires four fireworks, they must be aligned just so, too many coincidences. But the logic is enjoyable.

There are a good many novel uses of this pattern in more advanced ways that I don't need to duplicate here, the thread is clear. For this release of the solver I've included the two types above and will further document when or if I can code up more variants.