Comments...
Wednesday 21-Oct-2009
... by: Thesty
i think you guys are right that there is a mistake in the paragraph beginning: 'Looking at H6...'. but i think that paragraph is a 'red herring' - the mistake doesn't appear to affect the validity of the method. ignore that paragraph and just look at the next one.so we're looking at the paragraph that begins 'Let us conjecture'. it explains that if you put a 5 in H6 then that forces 9s into H4 and B6 and thus a 5 into B4. that array of 5s and 9s forms the deadly pattern i.e. if that were right then the final grid would have an alternative solution (with those 5s and 9s reversed). thus the 5 can't go in H6.
what do you think?
Friday 2-Oct-2009
... by: Otto
I have the same question as Dean on 7-JUL-2009. What (or where) is your answer?Tuesday 7-Jul-2009
... by: Dean
I have the same question as Don above except I can see why 9 can't be at B6. What I don't understand is why 9 can't be at A4 and B2 in option A.Monday 6-Jul-2009
... by: Don
In figure 1, BH46, I don't understand how option A forces 9 at B4. If H6 is 9, why can't 9 be at A4 and B6? I'm not arguing; I just don't understand.Sunday 10-May-2009
... by: John
I used this technique librally for several months with success until today when it kept giving me an incorrect solution. I just want to confirm that the floor has to be in the same box for hidden type 2's to work, right?Yes


